[issue37494] Call asyncio Future in scope

[Fourcade]

New submission from Fourcade <robinf95 at yahoo.fr>:

I'm trying to get the progession of my asyncIO Futures. For some reason, I can't get value updates inside any other scope.

For example:

```
import concurrent.futures
import time
import asyncio
import random

def get_progress(futures):
    return sum([f.done() for f in futures])

def long_task(t):
    time.sleep(1.5)
    return t

loop = asyncio.get_event_loop()
executor = concurrent.futures.ProcessPoolExecutor(max_workers=4)
inputs = ['a', 'b', 'c', 'd', 'e', 'f', 'g']
futures_ = [loop.run_in_executor(executor, long_task, i) for i in inputs]

for i in range(5):
    time.sleep(1)
    print(get_progress(futures_))
```

It prints only 0. However, if I run this inside a terminal and call get_progress(futures_) it prints 7 as expected.

Am I missing something here ?

----------
components: asyncio
messages: 347232
nosy: RobinFrcd, asvetlov, yselivanov
priority: normal
severity: normal
status: open
title: Call asyncio Future in scope
type: behavior
versions: Python 3.6

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue37494>
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