[issue36887] Add integer square root, math.isqrt

[Steven D'Aprano]

Steven D'Aprano <steve+python at pearwood.info> added the comment:

Yes please for this!

The two usual versions are isqrt and nsqrt:

isqrt(n) = largest integer ≤ √n

nsqrt(n) = closest integer to √n

although to be honest I'm not sure what use cases there are for nsqrt.

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nosy: +steven.daprano

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<https://bugs.python.org/issue36887>
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