[issue41232] Python `functools.wraps` doesn't deal with defaults correctly

[Jelle Zijlstra]

Jelle Zijlstra <jelle.zijlstra at gmail.com> added the comment:

We should not do this, because the wrapping function may have different defaults, and updating __defaults__ would make it use the wrapped function's defaults.

Example:

>>> def f(y=1):
...     print(y)
... 
>>> f()
1
>>> f.__defaults__
(1,)
>>> f.__defaults__ = ()
>>> f()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: f() missing 1 required positional argument: 'y'

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nosy: +Jelle Zijlstra

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue41232>
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