[Python-checkins] python/dist/src/Lib/test test_heapq.py,1.4,1.5
tim_one@users.sourceforge.net
tim_one@users.sourceforge.net
Fri, 02 Aug 2002 19:11:28 -0700
Update of /cvsroot/python/python/dist/src/Lib/test
In directory usw-pr-cvs1:/tmp/cvs-serv18315/python/lib/test
Modified Files:
test_heapq.py
Log Message:
Minor fiddling, including a simple class to implement a heap iterator
in the test file. I have docs for heapq.heapify ready to check in, but
Jack appears to have left behind a stale lock in the Doc/lib directory.
Index: test_heapq.py
===================================================================
RCS file: /cvsroot/python/python/dist/src/Lib/test/test_heapq.py,v
retrieving revision 1.4
retrieving revision 1.5
diff -C2 -d -r1.4 -r1.5
*** test_heapq.py 2 Aug 2002 21:48:06 -0000 1.4
--- test_heapq.py 3 Aug 2002 02:11:26 -0000 1.5
***************
*** 13,16 ****
--- 13,30 ----
verify(heap[parentpos] <= item)
+ # An iterator returning a heap's elements, smallest-first.
+ class heapiter(object):
+ def __init__(self, heap):
+ self.heap = heap
+
+ def next(self):
+ try:
+ return heappop(self.heap)
+ except IndexError:
+ raise StopIteration
+
+ def __iter__(self):
+ return self
+
def test_main():
# 1) Push 100 random numbers and pop them off, verifying all's OK.
***************
*** 48,52 ****
# 5) Less-naive "N-best" algorithm, much faster (if len(data) is big
# enough <wink>) than sorting all of data. However, if we had a max
! # heap instead of a min heap, it would go much faster still via
# heapify'ing all of data (linear time), then doing 10 heappops
# (10 log-time steps).
--- 62,66 ----
# 5) Less-naive "N-best" algorithm, much faster (if len(data) is big
# enough <wink>) than sorting all of data. However, if we had a max
! # heap instead of a min heap, it could go faster still via
# heapify'ing all of data (linear time), then doing 10 heappops
# (10 log-time steps).
***************
*** 54,62 ****
heapify(heap)
for item in data[10:]:
! if item > heap[0]: # this gets rarer and rarer the longer we run
heappush(heap, item)
! heappop(heap)
! heap.sort()
! vereq(heap, data_sorted[-10:])
# Make user happy
if verbose:
--- 68,75 ----
heapify(heap)
for item in data[10:]:
! if item > heap[0]: # this gets rarer the longer we run
! heappop(heap) # we know heap[0] isn't in best 10 anymore
heappush(heap, item)
! vereq(list(heapiter(heap)), data_sorted[-10:])
# Make user happy
if verbose: