[Python-checkins] bpo-30004: Fix the code example of using group in Regex Howto Docs (GH-4443) (GH-4554)

[Mariatta]

https://github.com/python/cpython/commit/3e60747025edc34b503397ab8211be59cfdd05cd
commit: 3e60747025edc34b503397ab8211be59cfdd05cd
branch: 3.6
author: Miss Islington (bot) <31488909+miss-islington at users.noreply.github.com>
committer: Mariatta <Mariatta at users.noreply.github.com>
date: 2017-11-24T21:03:04-08:00
summary:

bpo-30004: Fix the code example of using group in Regex Howto Docs (GH-4443) (GH-4554)

The provided code example was supposed to find repeated words, however it returned false results.
(cherry picked from commit 610e5afdcbe3eca906ef32f4e0364e20e1b1ad23)

files:
M Doc/howto/regex.rst

diff --git a/Doc/howto/regex.rst b/Doc/howto/regex.rst
index 7ff4563d14f..eef63478bee 100644
--- a/Doc/howto/regex.rst
+++ b/Doc/howto/regex.rst
@@ -844,7 +844,7 @@ backreferences in a RE.
 
 For example, the following RE detects doubled words in a string. ::
 
-   >>> p = re.compile(r'(\b\w+)\s+\1')
+   >>> p = re.compile(r'\b(\w+)\s+\1\b')
    >>> p.search('Paris in the the spring').group()
    'the the'
 
@@ -943,9 +943,9 @@ number of the group.  There's naturally a variant that uses the group name
 instead of the number. This is another Python extension: ``(?P=name)`` indicates
 that the contents of the group called *name* should again be matched at the
 current point.  The regular expression for finding doubled words,
-``(\b\w+)\s+\1`` can also be written as ``(?P<word>\b\w+)\s+(?P=word)``::
+``\b(\w+)\s+\1\b`` can also be written as ``\b(?P<word>\w+)\s+(?P=word)\b``::
 
-   >>> p = re.compile(r'(?P<word>\b\w+)\s+(?P=word)')
+   >>> p = re.compile(r'\b(?P<word>\w+)\s+(?P=word)\b')
    >>> p.search('Paris in the the spring').group()
    'the the'