[Python-checkins] bpo-36138: Clarify docs about converting datetime.timedelta to scalars. (GH-12137)

[Nick Coghlan]

https://github.com/python/cpython/commit/f40b4a0b6277b2779b9ded3736325489f2af93e4
commit: f40b4a0b6277b2779b9ded3736325489f2af93e4
branch: master
author: Yasser A <yalshalaan at gmail.com>
committer: Nick Coghlan <ncoghlan at gmail.com>
date: 2019-03-16T13:56:58+10:00
summary:

bpo-36138: Clarify docs about converting datetime.timedelta to scalars. (GH-12137)

Be explicit that timedelta division converts an overall duration to the interval
units given by the denominator.

files:
A Misc/NEWS.d/next/Documentation/2019-03-02-00-40-57.bpo-36138.yfjNzG.rst
M Doc/library/datetime.rst

diff --git a/Doc/library/datetime.rst b/Doc/library/datetime.rst
index 121f73bbe852..1ee23c2175a2 100644
--- a/Doc/library/datetime.rst
+++ b/Doc/library/datetime.rst
@@ -254,8 +254,9 @@ Supported operations:
 |                                | rounded to the nearest multiple of            |
 |                                | timedelta.resolution using round-half-to-even.|
 +--------------------------------+-----------------------------------------------+
-| ``f = t2 / t3``                | Division (3) of *t2* by *t3*.  Returns a      |
-|                                | :class:`float` object.                        |
+| ``f = t2 / t3``                | Division (3) of overall duration *t2* by      |
+|                                | interval unit *t3*. Returns a :class:`float`  |
+|                                | object.                                       |
 +--------------------------------+-----------------------------------------------+
 | ``t1 = t2 / f or t1 = t2 / i`` | Delta divided by a float or an int. The result|
 |                                | is rounded to the nearest multiple of         |
@@ -351,7 +352,8 @@ Instance methods:
 .. method:: timedelta.total_seconds()
 
    Return the total number of seconds contained in the duration. Equivalent to
-   ``td / timedelta(seconds=1)``.
+   ``td / timedelta(seconds=1)``. For interval units other than seconds, use the
+   division form directly (e.g. ``td / timedelta(microseconds=1)``).
 
    Note that for very large time intervals (greater than 270 years on
    most platforms) this method will lose microsecond accuracy.
diff --git a/Misc/NEWS.d/next/Documentation/2019-03-02-00-40-57.bpo-36138.yfjNzG.rst b/Misc/NEWS.d/next/Documentation/2019-03-02-00-40-57.bpo-36138.yfjNzG.rst
new file mode 100644
index 000000000000..f5352bb3958f
--- /dev/null
+++ b/Misc/NEWS.d/next/Documentation/2019-03-02-00-40-57.bpo-36138.yfjNzG.rst
@@ -0,0 +1 @@
+Improve documentation about converting datetime.timedelta to scalars.