[Python-checkins] bpo-40340: Separate examples more clearly in the programming FAQ (GH-19688)

Cajetan Rodrigues webhook-mailer at python.org
Fri Apr 24 19:39:12 EDT 2020


https://github.com/python/cpython/commit/5aafa548794d23b6d4cafb4fd88289cd0ba2a2a8
commit: 5aafa548794d23b6d4cafb4fd88289cd0ba2a2a8
branch: master
author: Cajetan Rodrigues <caje731 at gmail.com>
committer: GitHub <noreply at github.com>
date: 2020-04-24T19:39:04-04:00
summary:

bpo-40340: Separate examples more clearly in the programming FAQ (GH-19688)

files:
M Doc/faq/programming.rst

diff --git a/Doc/faq/programming.rst b/Doc/faq/programming.rst
index 70b11d6e93056..68f9ce811a641 100644
--- a/Doc/faq/programming.rst
+++ b/Doc/faq/programming.rst
@@ -851,10 +851,11 @@ For integers, use the built-in :func:`int` type constructor, e.g. ``int('144')
 e.g. ``float('144') == 144.0``.
 
 By default, these interpret the number as decimal, so that ``int('0144') ==
-144`` and ``int('0x144')`` raises :exc:`ValueError`. ``int(string, base)`` takes
-the base to convert from as a second optional argument, so ``int('0x144', 16) ==
-324``.  If the base is specified as 0, the number is interpreted using Python's
-rules: a leading '0o' indicates octal, and '0x' indicates a hex number.
+144`` holds true, and ``int('0x144')`` raises :exc:`ValueError`. ``int(string,
+base)`` takes the base to convert from as a second optional argument, so ``int(
+'0x144', 16) == 324``.  If the base is specified as 0, the number is interpreted
+using Python's rules: a leading '0o' indicates octal, and '0x' indicates a hex
+number.
 
 Do not use the built-in function :func:`eval` if all you need is to convert
 strings to numbers.  :func:`eval` will be significantly slower and it presents a



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