[Python-Dev] zipfile.py
James C. Ahlstrom
jim@interet.com
Fri, 17 Dec 1999 09:39:51 -0500
"M.-A. Lemburg" wrote:
>
> "James C. Ahlstrom" wrote:
> > > ftp://ftp.interet.com/pub/pylib.html
> >
> Unfortunately, I always get the following traceback when trying
> to print the directory:
Yes, compression isn't there yet. I am looking into it.
> Some notes on the API:
> ----------------------
> * I would find it more convenient if the filename and mode
> would be constructor parameters, e.g.
>
> zfile = zipfile('myfile.zip','rb')
OK, done.
> with compression defaulting to 8 rather than 0 (most zip files
> will be deflated since this is the ZIP default).
Until compression works, and zlib ships with Python I
would rather default to no compression (method 0). Otherwise
this is not useful as a Python import archive.
> * Also, I would like a method much like the os.listdir()
> which returns a list of filenames rather than print it
> to stdout.
OK, done.
> * .is_zipfile() should probably be a separate function: it
> doesn't use any of the class' features.
OK, done.
> Aside: I found that you are using undocumented arguments to
> zlib.compressobj() ... are these extra arguments left out of
> the documentation on purpose or by simple oversight ? I couldn't
> find them in the HTML docs and neither in the docstrings.
I am following the CNRI code blindly here. I don't have
docs either.
JimA