[Python-Dev] Termination of two-arg iter()

[Greg Ewing]

> What about this example?
> >>> l = []
> >>> li = iter(l)
> >>> li.next()
> Traceback (most recent call last):
>   File "<stdin>", line 1, in ?
> StopIteration
> >>> l.extend([1, 2, 3])
> >>> li.next()
> 1
> 
> does the list iterator violate the proposed behavior?

Perhaps the docs should say something like "The next()
method raises StopIteration if there are no more items
remaining in the sequence at the time of the call."

This would both imply the repeated raising of
StopIteration in the case where the sequence hasn't
been modified in the meantime, and also allow the
above behaviour (which seems entirely logical, to
my way of thinking).

Greg Ewing, Computer Science Dept, +--------------------------------------+
University of Canterbury,	   | A citizen of NewZealandCorp, a	  |
Christchurch, New Zealand	   | wholly-owned subsidiary of USA Inc.  |
greg@cosc.canterbury.ac.nz	   +--------------------------------------+