[Python-Dev] funny leak

Tim Peters tim.one@comcast.net
Mon, 24 Mar 2003 10:57:04 -0500

[Christian Tismer]
> No, this is not the point. Don't call the function
> at all, just execute the above code and call
> gc.collect(). You will see one reference eaten
> every time you repeat this.

Can you show explicit evidence instead of trying to describe it?  Here's
what I tried:

def one():
    def conjoin(gs):
        def gen():
            gs      # unbreakable cycle
            gen     # unless one is commented out

import sys, gc
lastrc = 0
while 1:
    thisrc = sys.gettotalrefcount()
    print thisrc - lastrc,
    lastrc = thisrc

Running that program under a debug-build CVS Python shows no growth in
sys.gettotalrefcount() after the first two iterations.  It also displays no
process-size growth.  IOW, I see no evidence of any flavor of leak.

I don't claim that you don't, but I don't know what "just execute the above
code ... one reference eaten every time" *means*.  It can't mean executing
the specific program I pasted in above, because that simply doesn't eat a
reference each time.