[Python-Dev] Re: Decimal data type issues
Kevin Jacobs
jacobs at theopalgroup.com
Wed Apr 21 12:56:35 EDT 2004
Tim Peters wrote:
>[Kevin Jacobs]
>...
>
>
>>Hopefully this is somewhat clearer.
>>
>>
>
>Sorry, it really isn't to me. When you extract "a number" from one of your
>databases, what do you get from it, concretely? A triple of (decimal string
>with embedded decimal point, integer precision, integer scale)? An integer
>value with an integer scale? A decimal string w/o embedded decimal point
>and an integer scale? Etc.
>
Sorry for all of the unnecessary confusion. I am in and out of meetings
all of this
week and have been trying to keep up several technical conversations in
5 minute
breaks between sessions. As such, my examples were flawed. However, I now
have _10_ minutes, to answer some of your questions, so hopefully I can
explain slightly better.
First, I get decimal numbers from many database adapters, flat files,
XML files, in
a variety of string formats, mainly. Virtually all are decimal string
representations
(i.e., a string of numbers with an option decimal point thrown in
somewhere). Not
all of them encode scale explicitly by adding trailing zeros, though
most of the time
do they conform to a given maximum precision. A few sources do provide
decimals
as an integer with an explicit decimal scale exponent.
>>Thus, I would like to create decimal instances that conform to those
>>schema -- i.e., they would be rounded appropriately and overflow errors
>>generated if they exceeded either the maximum precision or scale. e.g.:
>>
>> Decimal('20000.001', precision=4, scale=0) === Decimal('20000')
>> Decimal('20000.001', precision=4, scale=0) raises an overflow exception
>>
>>
>
>The inputs on those two lines look identical to me, so I'm left more lost
>than before -- you can't really want Decimal('20000.001', precision=4,
>scale=0) *both* to return 20000 *and* raise an overflow exception.
>
>
Clearly not. The first example was supposed to have a precision of 5:
Decimal('20000.001', precision=5, scale=0) === Decimal('20000')
>In any case, that's not what the IBM standard supports. Context must be
>respected in its abstract from-string operation, and maximum precision is a
>component of context. If context's precision is 4, then
>
> from-string('20000.001')
>
>would round to the most-significant 4 digits (according to the rounding mode
>specified in context), and signal both the "inexact" and "rounded"
>conditions. What "signal" means: if the trap-enable flags are set in
>context for either or both of those conditions, an exception will be raised;
>if the trap-enable flags for both of those conditions are clear, then the
>inexact-happened and rounded-happened status flags in context are set, and
>you can inspect them or not (as you please).
>
>
Yes -- this is what I would like to have happen, but with a short-cut to
support this
common operation. My previous comment about "great difficulty" was not
in terms
of the implementation, but rather the number of times it would have to
be developed
independently, if not readily available.
However, I am still not aware of a trivial way to enforce a given scale
when creating
decimal instances. As you point out in a separate e-mail, there are
many operations
that in effect preserve scale due to unnormalized arithmetic operations.
However, this conversation is somewhat academic since there does not seem
to be a consensus that adding support for construction with scale and
precision
parameters are of general use. So I will create my own decimal subclass
and/or
utility function and be on my merry way.
Thanks,
-Kevin
More information about the Python-Dev
mailing list