[Python-Dev] cmp(x,x)
Greg Ewing
greg at cosc.canterbury.ac.nz
Sun May 23 20:40:21 EDT 2004
Gustavo Niemeyer <niemeyer at conectiva.com>:
> Is it true that the current list comparison algorithm
> goes trough every element doing identity comparison, and
> if every element in the first list *is* the element at
> the same position in the second list, and the list has
> the same size, then lists are considered equal?
> If that's true, then I belive there's no reason for
> not comparing if the first list *is* the second list at
> the top of list_richcompare(), right?
What if the list contains a NaN?
Greg Ewing, Computer Science Dept, +--------------------------------------+
University of Canterbury, | A citizen of NewZealandCorp, a |
Christchurch, New Zealand | wholly-owned subsidiary of USA Inc. |
greg at cosc.canterbury.ac.nz +--------------------------------------+
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