[Python-Dev] Re: anonymous blocks
reinhold-birkenfeld-nospam at wolke7.net
Fri Apr 22 19:20:46 CEST 2005
Nick Coghlan wrote:
> Interestingly, with this approach, "for dummy in my_resource()" would still wrap
> the block of code in the entrance/exit code (because my_resource *is* a
> generator), but it wouldn't get the try/finally semantics.
> An alternative would be to replace the 'yield None' with a 'break' or
> 'continue', and create an object which supports the resource protocol and NOT
> the iterator protocol. Something like:
> def my_resource():
> print "Hi!" # Do entrance code
> continue # Go on with the contents of the 'with' block
> print "Bye!" # Do exit code
> (This is currently a SyntaxError, so it isn't ambiguous in any way)
Oh, it is ambiguous, as soon as you insert a for/while statement in your resource
function and want to call continue in there. Other than that, it's very neat.
Maybe "yield" alone (which is always a SyntaxError) could be used.
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