[Python-Dev] Using descriptors to dynamically attach methods
written in Python to C-defined (new-style) types
Bob Ippolito
bob at redivi.com
Sat Mar 26 01:39:46 CET 2005
On Mar 25, 2005, at 6:13 PM, Travis Oliphant wrote:
> In updating Numeric to take advantage of the new features in Python,
> I've come across the need
> to attach a Python-written function as a method to a C-builtin. I
> don't want to inherit, I just want to extend the methods of a builtin
> type using a Python function. I was thinking of updating the new
> type objects dictionary with a new entry that is a descriptor object.
You probably do want to inherit at least once from Python, see below.
> It seems that the descriptor mechanism makes this a relatively
> straightforward thing. My question is, can I use the
> already-available Descriptor objects to do this, or will I need to
> define another Descriptor object. (Perhaps a PythonMethod descriptor
> object to complement the Method Descriptor).
> Any hints will be helpful.
If the type object does have a mutable dictionary (not a read-only
dictproxy), you're pretty much already done. Functions implement the
descriptor protocol, presumably even in the way you want them to.
Meaning, if you just stick a function into a (new style) class dict,
when you fetch it from an instance you'll end up with a bound method.
When you fetch it from the class, you end up with an unbound method.
There's no noticeable difference between if you did this, or if the
class had the function when it was defined. Functions (aka methods)
defined in a class body are *nothing special*.
However, by default, extension types don't have a dict and the easiest
way to get one is just to subclass it from Python. So, what you can do
is simply not make the C types part of the public API, use subclasses
of them as the API for the classes that you need/want to be extensible
in this manner. This is the reason you can't do "object.foo = 1" but
you CAN do it to any Python subclass of object (unless you explicitly
disallow it by way of metaclass or slots).
-bob
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