[Python-Dev] Any reason that any()/all() do not take apredicateargument?

[Raymond Hettinger]

[Bill Janssen]
> Yeah, but you can't do more complicated expressions that way, like
>
>      any(lambda x: x[3] == "thiskey")

You're not making any sense.  The sequence argument is not listed and the lambda 
is unnecessary.  Try this instead:

     any(x[3] == 'thiskey' for x in seq)


> I think it makes a lot of sense for any and all to take optional
> predicate function arguments.

I think you don't understand what you already have to work with in Py2.5a -- a 
boolean expression in a genexp should always suffice -- no separate lambda based 
predicate function is ever required.


Raymond