[Python-Dev] SyntaxError: can't assign to function call
Neal Becker
ndbecker2 at gmail.com
Wed Aug 9 20:10:15 CEST 2006
Terry Reedy wrote:
>
> "Neal Becker" <ndbecker2 at gmail.com> wrote in message
> news:ebd2sp$nnv$1 at sea.gmane.org...
>> class X (object):
>> pass
>>
>> X() += 2
>>
>>> SyntaxError: can't assign to function call
>>
>> Suppose I actually had defined __iadd__ for class X. Python says this
>> syntax is invalid. I wish is wasn't.
>
> If you translate to x() = x() +2, with x called just once, it does not
> make
> sense. You can bind to names and slots in compound objects, but not to
> objects.
>
>> Here's where I might use it. Suppose I have a container class. Suppose
>> I
>> could make a slice of this container, like so:
>>
>> c = Container()
>> s = Slice (c, 0, 10)
>>
>> where "Slice" is a class. Then:
>>
>> s += 2
>>
>> Would perform iadd on the slice of the container. A convenient syntax
>> would
>> be:
>>
>> Slice (c, 0, 10) += 2
>
> If this were made to work, the unbound object you are making an
> 'assignment' to, purely for side effect, would disappear. So if you don't
> want a separate object to be named and kept around, give your container a
> sliceadd method:
> c.sliceadd((0,10), 2)
>
>>
>> Does anyone else think this would be a good addition to Python?
>
> I don't. Augmented assigment is confusing enough to many.
>
I guess I confused things with the augmented assignment. It's not a
question specific to augmented assignment. There are 2 questions:
1) Should assignment to a temporary object be allowed?
2) Should the syntax for creation of a temporary object be a constructor
call?
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