[Python-Dev] any support for a methodcaller HOF?

[Eric Nieuwland]

On 4 feb 2006, at 3:18, Nick Coghlan wrote:
> All I'm suggesting is that a similarly inspired syntax is worth
> considering when it comes to deferred expressions:
>
>    def f(x):
>      return x*x
>
> => f = (x*x def (x))

It's not the same, as x remains free whereas in g = [x*x for x in seq] 
x is bound.

Yours is

f = lambda x: x*x

and it will die by Guido hand...
--eric