[Python-Dev] UUID module

[Thomas Heller]

Phillip J. Eby wrote:
> At 06:39 PM 6/10/2006 +0200, Thomas Heller wrote:
>>I don't know if this is the uuidgen you're talking about, but on linux there
>>is libuuid:
>>
>> >>> from ctypes import *
>> >>> lib = CDLL("libuuid.so.1")
>> >>> uuid = create_string_buffer(16)
>> >>> lib.uuid_generate(byref(uuid))
>>2131088494
>> >>> from binascii import hexlify
>> >>> hexlify(buffer(uuid))
>>'0c77b6d7e5f940b18e29a749057f6ed4'
>> >>>
> 
> Nice.  :)  But no, this one's a uuidgen() system call on FreeBSD>=5.0 and 
> NetBSD>=2.0; it may be in other BSD variants as well... perhaps OS X?

For completeness :-), although its probably getting off-topic:

$ uname -a
FreeBSD freebsd 6.0-RELEASE FreeBSD 6.0-RELEASE #0: Thu Nov  3 09:36:13 UTC 2005     root at x64.samsco.home:/usr/obj/usr/src/sys/GENERIC  i386
$ python
Python 2.4.1 (#2, Oct 12 2005, 01:36:32)
[GCC 3.4.4 [FreeBSD] 20050518] on freebsd6
Type "help", "copyright", "credits" or "license" for more information.
>>> from ctypes.util import find_library
>>> find_library("c")
'libc.so.6'
>>> from ctypes import *
>>> libc = CDLL("libc.so.6")
>>> uuid = create_string_buffer(16)
>>> libc.uuidgen(uuid, 1)
0
>>> uuid[:]
'\xd2\xff\x8e\xe3\xa3\xf8\xda\x11\xb0\x04\x00\x0c)\xd1\x18\x06'
>>>
$

On OS X, this call is not available, but /usr/lib/libc.dylib
has a uuid_generate function which is apparently compatible to
the linux example I posted above.

Thomas