[Python-Dev] splitext('.cshrc')

"Martin v. Löwis" martin at v.loewis.de
Thu Mar 8 18:54:30 CET 2007

Scott David Daniels schrieb:
>   c) Given a filename, make an appropriately named associated file.
>         pyo_name = os.path.splitext(name)[0] + '.pyo'
>      This argues for os.path.splitext('.pythonrc') == ('.pythonrc','')

Indeed, somebody found that people apparently do

     back_name = splitext(name[0]) + '.bak'

which would severely break if somebody tried to create backups of 
dotfiles that way.


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