[Python-Dev] splitext('.cshrc')

["Martin v. Löwis"]

Scott David Daniels schrieb:
>   c) Given a filename, make an appropriately named associated file.
>         pyo_name = os.path.splitext(name)[0] + '.pyo'
>      This argues for os.path.splitext('.pythonrc') == ('.pythonrc','')

Indeed, somebody found that people apparently do

     back_name = splitext(name[0]) + '.bak'

which would severely break if somebody tried to create backups of 
dotfiles that way.

Regards,
Martin