[Python-Dev] Missing operator.call

[Greg Ewing]

Stephen J. Turnbull wrote:
> Greg Ewing writes:
> 
>  > The fact that yielding is going on is not of
>  > interest in that situation
> 
> But doesn't "yield" in the sense of "yield the right of way" mean
> exactly that?

I've no problem with using 'yield' when actually
giving up control. But the code making the call doesn't
think of itself as yielding. The called code may
want to yield, but the caller doesn't care about
that. It just wants to make the callee do its thing,
whatever it is.

Ideally the caller would be able to use a normal
function call, but Python generators don't work
that way. The next best thing is a slightly
different form of call syntax.

-- 
Greg