[Python-Dev] yield * (Re: Missing operator.call)

[Georg Brandl]

glyph at divmod.com schrieb:
> On 01:00 am, greg.ewing at canterbury.ac.nz wrote:
>>Guido van Rossum wrote:
>>>We already have yield expressions and they mean something else...
>>
>>They don't have a "*" in them, though, and I don't
>>think the existing meaning of yield as an expression
>>would carry over into the "yield *" variant, so there
>>shouldn't be any conflict.
>>
>>But if you think there will be a conflict, or that the
>>similarity would be too confusing, maybe the new
>>construct should be called something else. I'm
>>open to suggestions.
> 
> I'm *already* regretting poking my head into this particular bike shed, 
> but...
> 
> has anyone considered the syntax 'yield from iterable'?  i.e.

Yes, basically the "yield *" and "yield from" are the two possibilities
that come up every once in a while.

Would that someone wrote a PEP, so that we can get a decision at some time.

Georg

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