[Python-Dev] PEP 3142: Add a "while" clause to generator expressions
Gerald Britton
gerald.britton at gmail.com
Mon Jan 19 17:37:23 CET 2009
Sure: Say I implement the sieve of Eratosthenes as a prime number
generator. I want some primes for my application but there are an
infinite number of primes. So I would like to write:
prime = (p for p in sieve() while p < 1000)
instead of:
import itertools
prime = takewhile(lamda p:p<1000, sieve())
to get the primes under 1000.
On Mon, Jan 19, 2009 at 11:15 AM, Daniel Stutzbach
<daniel at stutzbachenterprises.com> wrote:
> On Mon, Jan 19, 2009 at 9:10 AM, Gerald Britton <gerald.britton at gmail.com>
> wrote:
>>
>> g = (n for n in range(100) if n*n < 50)
>>
>> would yield 0, 1, 2, 3, 4, 5, 6 and 7, but would also consider
>> the numbers from 8 to 99 and reject them all since n*n >= 50 for
>> numbers in that range. Allowing for a "while" clause would allow
>> the redundant tests to be short-circuited:
>
> Instead of using a "while" clause, the above example could simply be
> rewritten:
>
> g = (n for n in range(8))
>
> I appreciate that this is a toy example to illustrate the syntax. Do you
> have some slightly more complex examples, that could not be rewritten by
> altering the "in" clause?
>
> --
> Daniel Stutzbach, Ph.D.
> President, Stutzbach Enterprises, LLC
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