[Python-Dev] operator precedence of __eq__, __ne__, etc, if both object have implementations

[Chris Withers]

Mark Dickinson wrote:
> I (still :-) think this is covered, for Python 2.x at least, by:
> 
> http://docs.python.org/reference/datamodel.html#coercion-rules

But this isn't coercion! :-)

> - For objects x and y, first x.__op__(y) is tried. If this is not
> implemented or returns NotImplemented, y.__rop__(x) is tried. 

Also, the above is not so:

Python 2.5.1
 >>> class X:
...   def __eq__(self,other):
...     print "X __eq__"
 >>> class Z: pass
...
 >>> Z()==X()
X __eq__

No __req__ in sight...

cheers,

Chris

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