[Python-Dev] Why is nan != nan?

[Curt Hagenlocher]

On Thu, Mar 25, 2010 at 7:54 AM, Mark Dickinson <dickinsm at gmail.com> wrote:
>
> Hmm. I take it back.  I was being confused by the fact that sqrt(nan)
> returns a nan with a new identity;  but it does apparently preserve
> the payload.  An example:

I played with this some a few months ago, and both the FPU and the C
libraries I tested will preserve the payload. I imagine Python just
inherits their behavior.

--
Curt Hagenlocher
curt at hagenlocher.org