[Python-Dev] __setcall__

[Benjamin Peterson]

2010/10/24 Bj Raz <whitequill.bj at gmail.com>:
> I was looking for a way to set a function being equal to another function:
> q(m+1) = q(m)+ ((-1)^m) * exp(lnanswer);
> I was hoping to use something like this:
> (q).__setcall__.(m+1) = (q).__setcall__.(m)+ ((-1)^m) * exp(lnanswer);
> As a work around.
> But I have not found the `__setcall__' built in being there.
>
> Here is the code block I'm working with:
>
> indvar = 200;
> q = 0;
> lnanswer = 0;
> for m = 1:150
>   lnanswer = (3 * m) * log(indvar) - log(factorial(3 * m))  ;
> q(m+1) = q(m)+ ((-1)^m) * exp(lnanswer);
> end
> lnanswer
> q
>
> Any help would be appreciated.

Please see python-list. This list is for the development of python.

The SAGE math package can do something like this.



-- 
Regards,
Benjamin