[Python-Dev] Hash collision security issue (now public)

[Christian Heimes]

Am 06.01.2012 03:04, schrieb Benjamin Peterson:
> It's obscure because hash('') != 0 doesn't necessarily mean the hashes
> are randomized. A different hashing algorithm could be in effect.

Also in 1 of 2**32 or 2**64 tries hash('') is 0 although randomizing is
active.

Christian