[Python-Dev] Hash collision security issue (now public)

Christian Heimes lists at cheimes.de
Fri Jan 6 03:09:55 CET 2012

Am 06.01.2012 03:04, schrieb Benjamin Peterson:
> It's obscure because hash('') != 0 doesn't necessarily mean the hashes
> are randomized. A different hashing algorithm could be in effect.

Also in 1 of 2**32 or 2**64 tries hash('') is 0 although randomizing is


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