[Python-Dev] Dinamically set __call__ method
Roberto Martínez
robertomartinezp at gmail.com
Tue Nov 4 17:52:39 CET 2014
Hi folks,
I am trying to replace dinamically the __call__ method of an object using
setattr.
Example:
$ cat testcall.py
class A:
def __init__(self):
setattr(self, '__call__', self.newcall)
def __call__(self):
print("OLD")
def newcall(self):
print("NEW")
a=A()
a()
I expect to get "NEW" instead of "OLD", but in Python 3.4 I get "OLD".
$ python2.7 testcall.py
NEW
$ python3.4 testcall.py
OLD
I have a few questions:
- Is this an expected behavior?
- Is possible to replace __call__ dinamically in Python 3? How?
Best regards,
Roberto
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