[Python-Dev] Definition of equality check behavior
Ethan Furman
ethan at stoneleaf.us
Tue May 7 20:23:09 EDT 2019
On 05/07/2019 02:05 PM, Jordan Adler wrote:
> Specifically, a comparison between a primitive (int, str, float were
> tested) and an object of a different type always return False,
> instead of raising a NotImplementedError. Consider `1 == '1'` as a
> test case.
If the object of a different type doesn't support comparing to an int, str, or float then False is the correct answer. On the other hand, if the object of a different type wants to compare equal to, say, ints then it will have to supply its own __eq__ method to return False/True as appropriate.
> Should the data model be adjusted to declare that primitive types are
> expected to fallback to False
No, because they aren't.
> or should the cpython primitive type's __eq__ implementation fallback
> to raise NotImplementedError?
No, because raising an error is not appropriate. Did you mean `return NotImplemented`? Because empirical evidence suggests that they do:
-------
class MyCustomInt():
def __init__(self, value):
self.value = value
def __eq__(self, other):
if isinstance(other, int):
return self.value == other
else:
return NotImplemented
def __ne__(self, other):
if isinstance(other, int):
return self.value != other
else:
return NotImplemented
core_int = 7
my_int = MyCustomInt(7)
print(core_int == my_int) # True
print(my_int == core_int) # True
-------
If the core types were not returning NotImplemented then the above would be False on the `core_int == my_int` line.
Hopefully this is clearer now?
--
~Ethan~
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