[Python-ideas] adding a trim convenience function
Tal Einat
taleinat at gmail.com
Thu Mar 6 00:06:01 CET 2008
Tal Einat wrote:
> Erick Tryzelaar wrote:
> > I find that when I'm normalizing strings, I end up writing this a lot:
> >
> > sites = ['www.google.com', 'http://python.org', 'www.yahoo.com']
> > new_sites = []
> > for site in sites:
> > if site.startswith('http://'):
> > site = site[len('http://'):]
> > new_sites.append(site)
> >
> > But it'd be much nicer if I could use a convenience function trim that
> > would do this for me, so I could just use a comprehension:
> >
> > def ltrim(s, prefix):
> > if s.startswith(prefix):
> > return s[len(prefix):]
> > return s
> >
> > sites = ['www.google.com', 'http://python.org', 'www.yahoo.com']
> > sites = [ltrim(site, 'http://') for site in sites]
> >
> > Would there be any interest to add this helper function, as well as an
> > "rtrim" and "trim", to the str class?
> >
>
> I'm against adding this as a string method, or even a a function in the stdlib.
>
> I've done a lot of text processing with Python and have hardly ever
> needed something like this. If you think this would be useful often, a
> good way to convince this list is to show some examples of how it
> could improve code in the standard library, noting how common they
> are.
>
> In general, having a lot of string methods is very harmful because it
> makes learning Python a longer and more confusing process.
> Furthermore, this functionality is very simple and easy to implement,
> I just thought of 3 different ways [1] to implement this function in a
> simple, readable one-liner. For these reasons, unless you can show
> that this will be very useful very often, I'm against.
>
> - Tal
>
>
> [1]
> ltrim = lambda item, to_trim,: re.sub('^' + to_trim, '', item)
> ltrim = lambda item, x: item[0 if not item.startswith(x) else len(x):]
> ltrim = lambda item, to_trim: ''.join(item.split(to_trim, 1))
>
Ignore the third implementation, it's broken... here's another one in its place:
ltrim = lambda item, x: item[item.startswith(x) * len(x):]
- Tal
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