[Python-ideas] Accessing the result of comprehension's expression from the conditional

[Ben Finney]

Lie Ryan <lie.1296 at gmail.com> writes:

> Steven D'Aprano wrote:
> <snip>
> > The only case it doesn't cover is where the second filter depends on
> > the value of x, and even that can be covered with a *tiny* bit more
> > work:
> > 
> > gen = ((x, 3*x**2-5*x+4) for x in seq if x % 3 != 2)
> > result = [y[1] for y in gen if -y[0] < y[1] < y[0]]
> > 
> > It requires no new syntax, no changes to the behaviour of list
> > comps, no new meaning on "as", it's understandable and readable.

I think it would be more readable without index references, but instead
using tuple unpacking::

    gen = ((x, 3*x**2-5*x+4) for x in seq if x % 3 != 2)
    result = [b for (a, b) in gen if -a < b < a]

It can even be done as a single expression without (IMO) significantly
affecting readability::

    result = [
        b for (a, b) in
            ((x, 3*x**2-5*x+4) for x in seq if x % 3 != 2)
        if -a < b < a]

> > Compare your suggestion:
> > 
> > [3*x**2-5*x+4 as y for x in seq if (x % 3 != 2) and (-x < y < x)]
> 
> For me, this one is much clearer, understandable, and readable than
> y[0] and y[1]; and you still have the option to split them if you
> think y[0] and y[1] is better.

I hope you'll agree that my above suggestion retains this, without
needing any new syntax.

-- 
 \        “If you go to a costume party at your boss's house, wouldn't |
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Ben Finney