[Python-ideas] Default arguments in Python - the return - running out of ideas but...

[Gerald Britton]

print(print) is not a function call in 2.x:

>>> import types
>>> def f(): pass
...
>>> isinstance(f, types.FunctionType)
True
>>> isinstance(print, types.FunctionType)
  File "<stdin>", line 1
    isinstance(print, types.FunctionType)
                   ^
SyntaxError: invalid syntax
>>> p = "hi there"
>>> print p
hi there
>>> print(p)
hi there


(print_) is interpreted as an expression, which is then passed to the
print statement

On Wed, May 13, 2009 at 3:30 PM, Scott David Daniels
<Scott.Daniels at acm.org> wrote:
> spir wrote:
>>
>> My opinion on this is you're basically right. Even 'print' (for py<3.0)
>> could be an identifier you could use in an assignment (or in any value
>> expression), I guess, for parse patterns are different:
>>   print_statement : "print" expression
>>   assignment      : name '=' expression
>> So you can safely have "print" as name, or inside an expression. Even
>> "print print" should work !
>
> But you would not want
>    print print
> and
>    print(print)
> to have two different meanings.
> In Python, extra parens are fair around expressions,
> and print(print) is clearly a function call.
>
> --Scott David Daniels
> Scott.Daniels at Acm.Org
>
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-- 
Gerald Britton