[Python-ideas] Function caller in operator module

Terry Reedy tjreedy at udel.edu
Wed Mar 3 22:21:16 CET 2010

On 3/3/2010 2:48 PM, Mike Graham wrote:
> Most operations that are available using operators in Python are
> provided by the operator module, but calling functions is noticeably
> absent is calling functions. A user can slightly abuse
> operator.methodcaller('__call__', ...) to perform this operation, but
> that is far from ideal.
> Should operator grow a new function caller, such that
> operator.caller(*args, **kwargs)(f) returns f(*args, **kwargs)?

Use case?

> I have never personally needed this exact operation; it would be
> somewhat odd but not altogether unthinkable to sort a list of
> callables by their return values. The closes thing to this I have seen
> in the wild is map(apply, fs), which is limited to the no-arguments
> case. It is also possibly uglier than [f() for f in fs]. In any event,
> it's not even an option in Python 3.x.

And not needed, as you show.


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