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- #1

- Jan 17, 2013

- 1,667

\(\displaystyle \int^x_0 \frac{\operatorname{Li}_2(t)^2}{t}\, dt \,\,\,\,\,\,\, 0\leq x \leq 1\)

We define the following

\(\displaystyle \operatorname{Li}_2(x)^2 =\left( \int^x_0 \frac{\log(1-t)}{t}\, dt \right)^2\)

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