[Python-ideas] Make all keywords legal as an identifier
Masklinn
masklinn at masklinn.net
Tue Apr 26 10:56:38 CEST 2011
On 2011-04-26, at 09:15 , Cameron Simpson wrote:
>
> Contrived examples:
>
> # getting the "as" name from "foo"
> from foo import as
> # but did I mean "from foo import this as that" ?
If you did, you'll realize it quite soon as you'll be missing `that` in your local namespace? In any case, the statement is not ambiguous. Not for the machine, but not for humans either.
>
> # is this now a syntax error, since "as" is a name?
> with open("foo") as fp:
`as` could be used as a name, but would still be a keyword. This statement would be parsed as `with [expr] as [name]`, which is perfectly valid, why would there be a syntax error anywhere?
`with open ("foo") as as` would also be valid, though one could argue less readable.
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