[Python-ideas] Propagating StopIteration value
storchaka at gmail.com
Mon Oct 8 23:22:57 CEST 2012
On 07.10.12 22:18, Richard Oudkerk wrote:
> That means that all but the last return value is ignored. Why is the
> last return value any more important than the earlier ones?
Because I think the last return value more useful for idiom
lookahead = next(iterator)
iterator = itertools.chain([lookahead], iterator)
> ISTM it would make just as much sense to do
> def chain(*iterables):
> values = 
> for it in iterables:
> values.append(yield from it)
> return values
It changes the behavior for iterators. And now more difficult to get a
generator which yields and returns the same values as the original. We
need yet one wrapper.
return (yield from generator)[-1]
iterator = lastvalue(itertools.chain([lookahead], iterator))
Yes, it can work.
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