[Python-ideas] while conditional in list comprehension ??
Oscar Benjamin
oscar.j.benjamin at gmail.com
Thu Jan 31 12:08:58 CET 2013
On 31 January 2013 08:32, Nick Coghlan <ncoghlan at gmail.com> wrote:
> On Tue, Jan 29, 2013 at 10:35 PM, Joao S. O. Bueno
> <jsbueno at python.org.br> wrote:
>> On 29 January 2013 09:51, yoav glazner <yoavglazner at gmail.com> wrote:
>>> Here is very similar version that works (tested on python27)
>>>>>> def stop():
>>> next(iter([]))
>>>
>>>>>> list((i if i<50 else stop()) for i in range(100))
>>> [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20,
>>> 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39,
>>> 40, 41, 42, 43, 44, 45, 46, 47, 48, 49]
>
> This actually prompted an interesting thought for me. The
> statement-as-expression syntactic equivalent of the "else stop()"
> construct would actually be "else return", rather than "else break",
> since the goal is to say "we're done", regardless of the level of loop
> nesting.
I'm not sure if it is the goal to be able to break out of any level of
nesting or at least that's not how I interpreted the original
proposal. It is what happens for this stop() function but only because
there's no other way.
Personally I don't mind as I generally avoid multiple-for
comprehensions; by the time I've written one out I usually decide that
it would be more readable as ordinary for loops or with a separate
function.
> It just so happens that, inside a generator (or generator expression)
> raising StopIteration and returning from the generator are very close
> to being equivalent operations, which is why the "else stop()" trick
> works. In a 3.x container comprehension, the inner scope is an
> ordinary function, so the equivalence between returning from the
> function and raising StopIteration is lost.
I don't really understand what you mean here. What is the difference
between comprehensions in 2.x and 3.x?
Oscar
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