[Python-ideas] os.path.here()

[Giampaolo Rodola']

On Wed, Feb 19, 2014 at 6:04 PM, Oscar Benjamin
<oscar.j.benjamin at gmail.com>wrote:

> On 19 February 2014 16:52, Giampaolo Rodola' <g.rodola at gmail.com> wrote:
> >
> > The implementation is pretty straightforward:
> >
> > def here(concat=None):
> >     """Return the absolute path of the parent directory where the
> >     script is defined.
> >     """
> >     here = os.path.abspath(os.path.dirname(__file__))
> >     if concat is not None:
> >         here = os.path.abspath(os.path.join(here, concat))
> >     return here
>
> So if I do from os.path import here and get the above function what
> happens when I call it in another module?
>

Ouch! You're right, I naively didn't take that into account. =)
I guess there are ways to inspect the caller's module name but I'm not
gonna push for that.
Sorry for the noise.
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