[Python-ideas] Unbounded range(), was Re: Allow __len__ to return infinity

[Ram Rachum]

I stand corrected.


On Tue, Feb 25, 2014 at 2:38 PM, Peter Otten <__peter__ at web.de> wrote:

> Ram Rachum wrote:
>
> > This actually makes me think that `range(int('inf'))` is a more elegant
> > construct than `itertools.count()`. Also `range(x, int('inf'))`
> > for `itertools.count(x)`,
>
> You could achieve that with range(None) or range(start, None)
> which would be similar to slices like items[start:None] aka items[start:].
>
> > and then you have `range(x, int('inf'), y)` or `range(0, int('-inf'),
> -1)`
> > which `itertools.count` can't cover.
>
> This *is* covered by count():
>
> >>> [x for x in itertools.islice(itertools.count(step=-2), 10)]
> [0, -2, -4, -6, -8, -10, -12, -14, -16, -18]
>
> All you save is one import. In return you'll see your applications break in
> new and interesting ways ;)
>
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