[Python-ideas] os.path.abspath - optional startdir argument

[Juancarlo Añez]

On a related topic...

What's missing in Python 3.4, is that most modules with functions or
methods that take file names or file paths as parameters are not
pathlib-aware, so a mandatory str(mypahtlibpath) is required.

For example, you cannot do:

f = open(Path(_file__) / 'app.conf')

It will fail.

But pathlib as part of the standard lib is new, so it's OK.

It will take time how know where in the module dependency hierarchy it
should belong.

Cheers,



On Thu, Jul 24, 2014 at 5:19 PM, Terry Reedy <tjreedy at udel.edu> wrote:

> On 7/24/2014 11:30 AM, Wolfgang Maier wrote:
>
>> On 24.07.2014 17:21, Juancarlo Añez wrote:
>>
>
>  Better yet, use the pathlib module.
>>>
>>
> Thank for the reminder. I took a better look at it.
>
>
>  As it stands, the pathlib module is only provisional plus,
>>
>
> 'Provisional' means that there *could* be a few api changes that would
> break code. The module is not going away.
>
>
>  IMO, kind of overkill for a simple task like that.
>>
>
> Overkill?
>
> import pathlib as path
> import os.path as path
>
> are equally easy
>
> The 'simple task' combines joining, normalizing, and 'absoluting'.
> pathlib.Path joins, Path.resolve normalizes and 'absolutes'. Together they
> combine the functions of os.path.join, os.path.abspath and
> os.path.normpath, with a nicer syntax, and with OS awareness.
>
> >>> path.Path('../../../Python27/lib', 'ast.py').resolve()
> WindowsPath('C:/Programs/Python27/Lib/ast.py')
>
> If one starts with a Path object, as would be typical, one can use '/' to
> join, as JuanCarlo mentioned.
>
> >>> base = path.Path('.')
> >>> (base / '../../../Python27/lib' / 'ast.py').resolve()
> WindowsPath('C:/Programs/Python27/Lib/ast.py')
>
> --
> Terry Jan Reedy
>
>
>
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-- 
Juancarlo *Añez*
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