[Python-ideas] Expose `itertools.count.start` and implement `itertools.count.__eq__` based on it, like `range`.

[Neil Girdhar]

That would be great.

On Friday, May 16, 2014 12:16:52 AM UTC-4, Antony Lee wrote:
>
> Actually, a more reasonable solution would be to have range handle keyword 
> arguments and map "range(start=x)" to "count(x)".  Or, perhaps more simply, 
> "range(x, None)" (so that no keyword arguments are needed).
>
>
> 2014-05-15 13:04 GMT-07:00 Ram Rachum <ram.r... at gmail.com <javascript:>>:
>
>> Now that I think about it, I would ideally want `itertools.count` to be 
>> deprecated in favor of `range(float('inf'))`, but I know that would never 
>> happen.
>>
>>
>> On Thursday, May 15, 2014 11:02:56 PM UTC+3, Ram Rachum wrote:
>>>
>>> I suggest exposing `itertools.count.start` and implementing 
>>> `itertools.count.__eq__` based on it. This'll provide the same benefits 
>>> that `range` got by exposing `range.start` and allowing `range.__eq__`.
>>>
>>
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