[Python-ideas] Make range objects orderable
MRAB
python at mrabarnett.plus.com
Fri Apr 24 02:31:05 CEST 2015
On 2015-04-24 01:15, Ethan Furman wrote:
> On 04/23, Riley Banks wrote:
>
>> I propose adding the ability to compare range objects using methods (e.g.
>> range.issubrange) and/or regular operators. Example:
>>
>> In [56]: range(0, 10, 3).issubrange(range(10))
>> Out[56]: True
>>
>> In [57]: range(0, 10, 3) <= range(10)
>> Out[57]: True
>>
>> In [58]: range(10) <= range(0, 10, 3)
>> Out[58]: False
>
> I seem to recall orderable ranges being rejected before. For example, is
> less-than, or subrange, dependent on the values themselves, or on the
> lowest and highest values, or on the start and end value, or ...
>
> In other words, given:
>
> a = range(11)
> b = range(12, step=3)
>
> is a < b, or b < a? Why?
>
It could be functionally equivalent to list(a) < list(b).
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