[Python-ideas] Why does sys.flags have both .interactive and .inspect?

[Alexander Walters]

On 8/23/2015 18:36, MRAB wrote:
> I tested it, and they _can_ be different.
>
> sys.flags.interactive will be true if you include the -i switch.
>
> sys.flags.inspect will be true if you include the -i switch or set the 
> PYTHONINSPECT environment
> variable.
>
> Thus, if you don't include the -i switch but _do_ set PYTHONINSPECT,  
> sys.flags.interactive will be
> false and sys.flags.inspect will be true.

That seams significant enough to be documented.  I'll work on a patch in 
the morning.