[Python-ideas] Float range class
Todd
toddrjen at gmail.com
Fri Jan 9 12:40:27 CET 2015
On Fri, Jan 9, 2015 at 12:28 PM, M.-A. Lemburg <mal at egenix.com> wrote:
> On 09.01.2015 12:01, Chris Angelico wrote:
> > On Fri, Jan 9, 2015 at 9:55 PM, M.-A. Lemburg <mal at egenix.com> wrote:
> >>> This is what I am talking about. The idea would be to have something
> that
> >>> is, as much as possible, identical to the existing range. I
> understand it
> >>> has floating-point issues, but any other approach would as well.
> >>
> >> This should do the trick:
> >>
> >> def frange(start, stop, steps):
> >> start = float(start)
> >> stop = float(stop)
> >> steps = int(steps)
> >> for i in range(steps + 1):
> >> yield ((steps - i) * start + i * stop) / steps
> >
> > Thing is, a range object is a lot more than just an iterable. In many
> > ways, it acts just like list(self) would - you can index it, slice it,
> > etc:
> >
> >>>> r = range(10, 101, 10)
> >>>> list(r)
> > [10, 20, 30, 40, 50, 60, 70, 80, 90, 100]
> >>>> r.index(70)
> > 6
> >>>> r[6]
> > 70
> >>>> len(r)
> > 10
> >>>> r[1:-4:2]
> > range(20, 70, 20)
> >
> > Does frange() need to be able to do all these operations?
> <snip>
> IMO, the only reason for having an frange() function in (probably)
> the math module is to provide an implementation which tries to
> reduce fp rounding problems to a minimum.
>
> Other than that, it's just too simple to add straight to the
> application code in a way which exactly fits the purpose and
> functionality needed by that application.
>
>
I think the wide usage of numpy.arange and numpy.linspace is evidence
against that conclusion.
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