[Python-ideas] allow `lambda' to be spelled λ

[Neil Girdhar]

On Tue, Jul 19, 2016 at 8:18 AM Rustom Mody <rustompmody at gmail.com> wrote:

>
> On Tuesday, July 19, 2016 at 5:06:17 PM UTC+5:30, Neil Girdhar wrote:
>>
>>
>> On Tue, Jul 19, 2016 at 7:21 AM Steven D'Aprano wrote:
>>
> On Mon, Jul 18, 2016 at 10:29:34PM -0700, Rustom Mody wrote:
>>>
>>> > IOW
>>> > 1. The lexer is internally (evidently from the error message) so
>>> > ASCII-oriented that any “unicode-junk” just defaults out to identifiers
>>> > (presumably comments are dealt with earlier) and then if that lexing
>>> action
>>> > fails it mistakenly pinpoints a wrong *identifier* rather than just an
>>> > impermissible character like python 2
>>>
>>> You seem to be jumping to a rather large conclusion here. Even if you
>>> are right that the lexer considers all otherwise-unexpected characters
>>> to be part of an identifier, why is that a problem?
>>>
>>
>> It's a problem because those characters could never be part of an
>> identifier.  So it seems like a bug.
>>
>
> An armchair-design solution would say: We should give the most appropriate
> answer for every possible unicode character category
> This would need to take all the Unicode character-categories and Python
> lexical-categories and 'cross-product' them — a humongous task to little
> advantage
>

I don't see why this is a "humongous task".  Anyway, your solution boils
down to the simplest fix in the lexer which is to block some characters
from matching any category, does it not?


>
> A more practical solution would be to take the best of the python2 and
> python3 current approaches:
> "Invalid character XX  in line YY"
> and just reveal nothing about what lexical category — like identifier —
> python thinks the  char is coming in.
>
> The XX is like python2 and the YY like python3
> If it can do better than '\xe2' — ie a codepoint — that’s a bonus but not
> strictly necessary
>
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