[Python-ideas] Showing qualified names when a function call fails

[Ryan Gonzalez]

I personally find it kind of annoying when you have code like this:


x = A(1, B(2, 3))


and Python's error message looks like this:


TypeError: __init__() takes 1 positional argument but 2 were given


It doesn't give much of a clue to which `__init__` is being called. At all.

The idea: when showing the function name in an error like this, show the
fully qualified name, like:


TypeError: A.__init__() takes 1 positional argument but 2 were given


This would be MUCH more helpful!


Another related change would be to do the same thing in tracebacks:


Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 2, in __init__
AssertionError


to:


Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 2, in MyClass.__init__
AssertionError


which could make it easier to find where exactly an error originated.

-- 
Ryan (ライアン)
[ERROR]: Your autotools build scripts are 200 lines longer than your
program. Something’s wrong.
http://kirbyfan64.github.io/
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