[Python-ideas] Make "yield" inside a with statement a SyntaxError

[Barry Scott]

On Wednesday, 8 August 2018 07:14:47 BST Ken Hilton wrote:
> Now, let's take a look at the following scenario:
> 
>     def read_multiple(*filenames):
>         for filename in filenames:
>             with open(filename) as f:
>                 yield f.read()

In this particular case you can fix the code:

    def read_multiple(*filenames):
        for filename in filenames:
            with open(filename) as f:
                result = f.read()
            yield result

Of course if you used readline() and not read() the problem returns.

But so long as you do not leak the generator the file will be closed 
immediately after the loop as the ref count of the generater hits 0.

Barry