[Python-ideas] add fluent operator to everything

[Anders Hovmöller]

I would suggest a small improvement: allow a trailing :: which is useful for when the last function does not return anything. So for example this

[1,2,3].append(4)::sort()

will evaluate to None, but 

[1,2,3].append(4)::sort()::

would evaluate to the list. 

> On 19 Feb 2019, at 15:13, Jimmy Girardet <ijkl at netc.fr> wrote:
> 
> Hi,
> 
> There was the discussion about vector, etc...
> 
> I think I have a frustration about chaining things easily in python in
> the stdlib where many libs like orm  do it great.
> 
> Here an example :
> 
> The code is useless, just to show the idea
> 
>>>> a = [1,2,3]
> 
>>>> a.append(4)
> 
>>>> a.sort()
> 
>>>> c = max(a) + 1
> 
> 
> I would be happy to have
> 
>>>> [1,2,3].append(4)::sort()::max() +1
> 
> It makes things very easy to read: first create list, then append 4,
> then sort, then get the max.
> 
> To resume, the idea is to apply via a new operator (::, .., etc...) the
> following callable on the previous object. It's clearly  for standalone
> object or after a method call when the return is None (there is fluent 
> `.` when there is a return value)
> 
>>> object::callable()  = callable(object)
>>> object(arg)::callable = callable(object(arg))
> 
> def callable(arg1,arg2):
>    pass
> 
>>> object::callable(arg) == callable(object, arg)
> 
> The idea is to use quite everything as first argument of any callable.
> 
> I do not know if it was already discussed, and if it would be
> technically doable.
> 
> Nice Day
> Jimmy
> 
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