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[Asaf Shakarchi]

Hello,

I have some directory that looks like this:



Dc=aup

Ou=customers

Ou=Customer's name

 

I just want to get a list of the customer's name,

There's anyway to do it? since search_s returns the entire line with the
whole DNS.

 

My code look like this:

 

import ldap

conn = ldap.initialize("ldap://ldap_server")

conn.set_option(ldap.VERSION, ldap.VERSION3)

conn.simple_bind_s(ADMIN_USER)

 

dn="ou=Customers,dc=alwaysup"

res = conn.search_s(dn, ldap.SCOPE_ONELEVEL, "objectClass=*", [])

 

for name,attrs in res:

  print name

 

ofcourse it prints the whole path, output is something like that:



ou=CustomerName,ou=Customers,dc=aup

 

I just want to get a list of 'CustomerName', even without the OU.

 

Well, I guess this is a python question, not an python-ldap one but
maybe there are some functions that make it easy to retrieve only
specific part of the result in python-ldap?



Thanks.

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