calldll windll instantiation

Karl & Mel llwo
Mon Apr 19 21:42:44 EDT 1999


Need some help.
I think?(scarry moment)? that I need to create more that one instance of a
dll.

1. Can this be done?
2. Is my sample even close?



"""gm_class  quick wrapper of dll functions"""

import windll
import time

class test:

    def __init__(self):
        self.gm=windll.module('GM4S32')

    def load_bde(self, SysDir='c:\\program files\\goldmine',
          GoldDir='c:\\program files\\goldmine\\gmbase',
          CommonDir='c:\\program files\\goldmine\\demo',
          User='PERACLES',
          Password=''):
        start=time.time()
        (SysDir, GoldDir, CommonDir,
         User, Password)=map(windll.cstring,(SysDir, GoldDir, CommonDir,
            User, Password))
        return (self.gm.GMW_LoadBDE(SysDir, GoldDir, CommonDir, User,
Password), "Startup Time: " + str(time.time()-start))

    def unload_bde(self):
        return self.gm.GMW_UnloadBDE()

...other defs...


>>> import gm_class
>>> a=gm_class.test()
>>> b=gm_class.test()
>>> a
<gm_class.test instance at 856fd0>
>>> b
<gm_class.test instance at 85b140>
>>> a.gm
<win32 module 'GM4S32' (0 functions)>
>>> b.gm
<win32 module 'GM4S32' (0 functions)>
>>> a.load_bde()                # This works
(1, 'Startup Time: 0.490000009537')
>>> a.gm
<win32 module 'GM4S32' (1 functions)>
>>> b.gm
<win32 module 'GM4S32' (1 functions)>
>>> b.load_bde()               # This fails but should work ;-(
(0, 'Startup Time: 0.0')
>>> a.gm
<win32 module 'GM4S32' (1 functions)>
>>> b.gm
<win32 module 'GM4S32' (1 functions)>
>>> a.gm==b.gm              # Don't know if this is correct
1
>>> a==b
0
>>>
>>> gm_class.windll.dump_module_info()
--------------------
WINDLL Function Call Stats:
--- <win32 module 'GM4S32' (1 functions)> ---
2 GMW_LoadBDE
>>>








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