Unsorting(randomizing) a sequence
tim_one at email.msn.com
Tue Aug 17 21:20:16 EDT 1999
> | def randomize(a, b):
> | return random.choice([-1, 0, 1])
> | l = range(2, 20)
> | l.sort(randomize)
> I'm not sure how robust this is. I've seen at least one implementation
> of qsort crash when given an inconsistent comparison function (e.g.,
> one that doesn't obey transitivity).
Python implements its own sort function (in 1.5.2 it's not quicksort, btw,
but a hybrid of common special cases, binary insertion and samplesort). A
very long time ago it used the platform qsort, but that blew up on some
systems; iirc, usually due to qsort being implemented non-reentrantly. The
current sort is robust against all that kind of stuff, including insane
comparison functions; it always returns *some* permutation of its input.
> And how is sort() supposed to know when it's done?
Surprisingly simple <wink>:
/* Find another slice to work on. */
if (--top < 0)
break; /* no more -- done! */
y'rs - tim
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